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The jq that is being executed via -exec creates a JSON object per found pathname. It strips off everything in the pathname up to the last slash for the name value, and uses the pathname as is for the path value. The final jq reads the data from find into an array with -s, and simply inserts it as the items array in a new JSON{"payload":{"allShortcutsEnabled":false,"fileTree":{"tools/programming/jq":{"items":[{"name":"01-text-to-json.md","path":"tools/programming/jq/01-text-to-json.md ...You can use the load_str operator to load a string from a file and assign its result to a property:. yq '.objects[0].tls.certificate = load_str("cert.pem")' template.yaml (above, template.yaml denotes path to your OpenShift template YAML file, if this wasn't obvious) The above command will produce the following output in your case:

jq -r (or jq --raw-output) I am using fastlane to do some dynamic changes to my iOS app's property list file. The sybtax goes like this: display_name: sh("jq -r .app_name ../billerConfig.json") display_name is the property of fastlane, which changes the name of my app. sh: signifies that we are trying to run a shell script in fastlaneThe backslash tells JavaScript (this has nothing to do with jQuery, by the way) that the next character should be interpreted as "special". In this case, an apostrophe after a backslash means to use a literal apostrophe but not to end the string. There are also other characters you can put after a backslash to indicate other special characters.That |= thing strikes me as the key here. Thanks for this! Glad you found an answer, and now I have one, too. I'll add that while not relevant to your particular example data, in some cases it might also be useful to do sort_by(.some_query_identifier|tonumber)-- to sort numerically by whatever field (.id as the .some_query_identifier in your case, but …Concatenate values from two JSON arrays by key · Issue #2373 · jqlang/jq · GitHub. jqlang / jq Public. Notifications. Fork 1.5k. Star 26k. Code. Issues 391. Pull requests 65. Actions.

By default jq prints a string output in double-quotes. If you want to remove the double quotes using raw option (-r) with jq to get the value of a string without the double-quotes. If you are fetching a number then this is not required as numbers are printed without any quotes. Here is a quick reference -. 1.String.concat () method accepts a list of strings as parameters and returns a new string after concatenation i.e. combination of all the strings. If the parameters are not strings, the concat () method firstly converts them into strings and then concatenation occurs. As we know that strings in JavaScript are immutable, so the concat () method ...The $.merge() operation forms an array that contains all elements from the two arrays. The orders of items in the arrays are preserved, with items from the second array appended. The $.merge() function is destructive. It alters the length and numeric index properties of the first object to include items from the second.. If you need the original first array, make a copy of it before calling ... ….

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The results should now be just one line, as jq is now just returning one single JSON array: When jq returns just one JSON object, the ‘Compact Output’ option will produce a one-line result. If you want to access just the first (or the n -th) item in an array, put a digit in the [] operator: .artObjects [0]Jul 20, 2021 · jq can reference expressions inside string using \(foo) [String interpolation - \(foo)][1] Inside a string, you can put an expression inside parens after a backslash. Whatever the expression returns will be interpolated into the string. jq '"The input was \(.), which is one less than \(.+1)"' <<< 42 Result: "The input was 42, which is one less ...

Here is the json paths which ends with 'headline' I have got: jq -c 'paths | select(.[-1] == "headline")' news.json ["data","legacyCollection","collectionsPage&q...This accesses the .children[] array of each .roots.bookmark_bar.children[] array entry and creates a string that is formatted according to what you showed in the question (with a tab character in-between the two pieces of data). If the double quotes are not necessary, you could change the cumbersome ["\"\(.name)\"",.url] to just [.name,.url].

dmv collier blvd jq -r '.parameters | .hostname,.lifecycle_environment' filename I got output like this: chi12ldmas01 Dev I got the same results with -c instead of -r, and also with -cr. So I simply made the results into an array, and joined them with a space, like this: jq -r '.parameters | [ .hostname,.lifecycle_environment ] | join(" ")' filename To get this: 1 99 summoning rs3can i go to nj dmv without appointment The + operator allows you to add two or more strings together. Note: See also the CONCAT() and CONCAT_WS() functions. Syntax. string1 + string2 + string_n. Parameter Values. Parameter Description; string1, string2, string_n: Required. The strings to add together: Technical Details. Works in:The jq expression [.a, .b, .c] extracts all the elements that we want from the input objects, and places them in an array. Some of these elements may be arrays, so we need to flatten all elements: taurus sun gemini rising 2 Answers. Sorted by: 139. Use fromjson. It parses a string to its appropriate json value. tojson (and @json) goes the other way around and takes a json value and converts it to a string. So you could do this: .response.text | fromjson.title.Use the select filter of jq: jq '.zk_kafka | .[] | select(.InstanceType == "t2.medium")' Use the --arg option to pass an argument to the query to avoid injections. costco blackout curtainsh49 oval white pillwww.itwemployee.com With jq's sub() and fromdate() functions: ... If your platform supports it, you could use the date functions to parse out then reformat the date string. home city ice employee portal About Strings. Recall that jq supports the same datatypes as JSON. JSON describes strings as: A string is a sequence of zero or more Unicode characters, wrapped in double quotes, using backslash escapes. Escape sequences. Within a string, use the backslash character to embed "special" characters: \" a literal quotation mark, \\ a literal backslash, jq 1.7 API documentation with instant search, offline support, keyboard shortcuts, mobile version, and more. used rail cars for salemyucf canvasfoothill aussies 2 Answers. Sorted by: 47. There is nothing wrong with syntax of. $ ('#part' + number).html (text); jQuery accepts a String ( usually a CSS Selector) or a DOM Node as parameter to create a jQuery Object. In your case you should pass a String to $ () that is. $ (<a string>) Make sure you have access to the variables number and text.